Errata edition 1.2¶

1. Page 87, text: Figure 3.5B … The bias voltage V1 compensates for this voltage. should be:

   The bias voltage V2 compensates for this voltage.

2. Page 145,equation (4.196) with the text below should be:

   \[f_{\ell}=\mathrm{KF} \frac{\pi}{3kTn\Gamma} f_T\]

   With \(n\Gamma\approx 1\) this simplifies to :math:`f_{ell}=253times 10^{18}textsc{kf} f_T.

3. Equation 10.6 should be:

   \[\lim_{H\rightarrow\infty}\left(\frac{E_o}{E_i}\right)=\frac{1}{k}\]

4. Figure 10.6 should be:

   

5. Figure 10.7 should be:

   

6. Section 11.4.6 should be:

   At low frequencies, zeros may cause the loop gain to drop below its midband value. In such cases the servo function obtains a high-pass character with a high-pass cut-off at \(\omega_{\ell}\). This cut-off frequency can be found in a similar way as the low-pass cut-off frequency \(\omega_{h}.\) We now only account for the \(p\) zeros and the \(q\) poles with frequencies smaller than \(\omega_{\ell}\) and use the asymptotic approximation according to (11.50) with \(p>q\). In this way we obtain:

   \[\omega_{\ell}\approx\sqrt[p-q]{\left\vert \frac{b_{\ell}}{a_{k}}\frac{{\displaystyle\prod\limits_{i=k+1}^{p}}% p_{i}}{{\displaystyle\prod\limits_{j=\ell+1}^{q}}z_{j}}\right\vert }.\]

7. Equation 12.5 should be:

   \[\omega_{h}=\left\vert a_{n}\right\vert ^{-\frac{1}{n}}\]

8. Equation 12.9 should be:

   \[\omega_{\ell}=\left\vert b_{k}\right\vert ^{-\frac{1}{k}}\]

9. Page 418: The text below equation (12.38) should be:

   From this, we see that a third-order system can be given an MFM characteristic with one negative real phantom zero if

10. Equation 12.62 should be:

    \[\omega_{h}=\sqrt[3]{\left\vert \frac{1}{a_{3}}\right\vert }\]

11. Page 428: The SLiCAP scripts that begins at line 20, should begin with line 19:

    result = pzLoopgain.results
    

12. Page 459: The text below Figure 12.74 should be:

    A phantom zero at \(s=-\frac{1}{R_c C_c}\) brings the two poles of the servo function into MFM positions.

13. Exercise 12.2: Change the value of the DC loop gain to \(-10^4\).

14. Figure 18.27 should be:

    

15. Equation 18.90 should be:

    \[\begin{split}\mathcal{R}=\mathcal{I}^{T}\mathbf{G}^{-1}\mathcal{I}=\left( \begin{array} [c]{ccc}% 0 & 1 & 0\\ 0 & 0 & 0\\ 1 & 0 & 0\\ 0 & 0 & 1 \end{array} \right) ^{T}\left( \begin{array} [c]{cccc}% \frac{1}{R_{1}}+\frac{1}{R_{2}} & -\frac{1}{R_{1}} & 0 & 0\\ -\frac{1}{R_{1}} & \frac{1}{R_{1}} & 0 & 1\\ 0 & 0 & 0 & -1\\ 0 & 1 & -1 & 0 \end{array} \right) ^{-1}\left( \begin{array} [c]{ccc}% 0 & 1 & 0\\ 0 & 0 & 0\\ 1 & 0 & 0\\ 0 & 0 & 1 \end{array} \right)\end{split}\]

16. Equation 18.91 should be:

    \[\begin{split}\mathcal{R}=\left( \begin{array} [c]{ccc}% R_{1}+R_{2} & R_{2} & -1\\ R_{2} & R_{2} & 0\\ -1 & 0 & 0 \end{array} \right) . \label{eq-Rmatrix}\end{split}\]

17. Equation 18.92 should be:

    \[\begin{split}\mathbf{T=}\mathcal{RC}\mathbf{=}\left( \begin{array} [c]{ccc}% R_{1}+R_{2} & R_{2} & -1\\ R_{2} & R_{2} & 0\\ -1 & 0 & 0 \end{array} \right) \left( \begin{array} [c]{ccc}% C_{1} & 0 & 0\\ 0 & C_{2} & 0\\ 0 & 0 & -L_{1}% \end{array} \right)\end{split}\]